"Unable to update wf field"

[zkx]

I had created a temp-talbe wf. The information appeared when I "assign" some values into it. I didn't find the reason.
Thank.

 

[Casper]

I suppose you mean that you get an error when you try to make an assign? If so, what error did you get? (errornumber and description)

Casper.

 

[zkx]

**Unable to update wf Field. (142)

Yes, it is the error message. Thanks

 

[TomBascom]

You will probably get much better answers if you post some sample code that illustrates the problem.

Don't just dump 500 lines of gibberish that results in an error into a posting -- try to trim down the sample code to something focused on the problem. And surround it with "

" tags so that it is nicely formatted.  (Use the "#" button in the posting editor...)

 

[sphipp]

You often get that if you try to assign something to a field without creating the record first. This should replicate the error.

def temp-table t
field t1 as char
field t2 as char.
release t.
t.t1 = "1".

I would guess that you have a procedure or block of code where you are assigning fields and another where you are creating a record and for some reason you are not calling the create procedure before the assign procedure.

 

[zkx]

Thanks for sphipp, TomBascom and Casper' help.
I had solved this question.

e.g.

for each xx1 no-lock...:
find first xx2 no-lock where xx2_field1 = xx1_field1 ... no-error.
if avail xx2 then do:
/*wf is a temp-table*/
create wf.
assgin wf_field1 = xx1_field1.
.
.
.
end.
else
do:
create wf. /*added this sentence*/ :blush1:
assign .
.
.
end.
end.