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Understand the OAuth 2.0 authorization code flow in Azure AD I have been doing a server to server communication using the code under. But now I have been told to use the above link for a server to server connection, but after reading it, I get an impression that I will be asked for username and password. Is it possible to use it for server to server communication? METHOD PUBLIC VOID LoginByClient(ipUri AS CHARACTER, ipClientId AS CHARACTER, ipClientSecret AS CHARACTER): ASSIGN APIUri = ipUri APIClientId = ipClientId APIClientSecret = ipClientSecret . oUri = NEW System.Uri(APIUri). System.Threading.Thread:Sleep(1000). System.Net.ServicePointManager:SecurityProtocol = System.Net.SecurityProtocolType:Tls12. oAuthParam = Microsoft.IdentityModel.Clients.ActiveDirectory.AuthenticationParameters:CreateFromResourceUrlAsync(oUri). System.Threading.Thread:Sleep(2000). oAuthContext = NEW Microsoft.IdentityModel.Clients.ActiveDirectory.AuthenticationContext(oAuthParam:Result:Authority). System.Threading.Thread:Sleep(2000). oClientCredential = NEW Microsoft.IdentityModel.Clients.ActiveDirectory.ClientCredential(APIClientId,APIClientSecret). System.Threading.Thread:Sleep(100). Token = oAuthContext:AcquireToken(oAuthParam:Result:Resource,oClientCredential):AccessToken. CATCH eAnySystem AS System.AggregateException : MESSAGE 'FEIL:' eAnySystem:GetMessage(1) view-as alert-box. END CATCH. CATCH eAny AS Progress.Lang.Error : MESSAGE 'FEIL:' eAny:GetMessage(1) VIEW-AS ALERT-BOX. StatusMessage = eAny:GetMessage(1). JBoxLogHandling:addLog('ERROR','Feilet ved henting av Token:' + eAny:GetMessage(1) + ' i ' + program-name(1)). END CATCH. END METHOD.
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